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Snowflake SnowPro Advanced: Data Scientist Certification Exam Sample Questions (Q137-Q142):
NEW QUESTION # 137
A data science team is using Snowpark ML to train a classification model. They want to log model metadata (e.g., training parameters, evaluation metrics) and artifacts (e.g., the serialized model file) for reproducibility and model governance purposes. Which of the following approaches is the most appropriate for integrating model logging and artifact management within the Snowpark ML workflow, minimizing operational overhead?
- A. Employ a separate, external model management platform (e.g., Databricks MLflow, SageMaker Model Registry) and configure Snowpark to interact with it via API calls during model training and deployment.
- B. Only track basic model performance metrics in a Snowflake table and rely on code versioning (e.g., Git) for model artifact management.
- C. Leverage the MLflow integration within Snowpark, utilizing its ability to track experiments, log parameters and metrics, and store model artifacts directly within Snowflake stages or external storage.
- D. Use a custom Python function to manually write model metadata to a Snowflake table and store the model file in a Snowflake stage.
- E. Serialize the model object to a string and store it as a VARIANT column in a Snowflake table, alongside the model metadata.
Answer: C
Explanation:
MLflow integration (B) within Snowpark provides a streamlined and integrated solution for model logging and artifact management, minimizing operational overhead by directly tracking experiments, logging parameters/metrics, and storing artifacts within Snowflake stages or external storage. Other options involve more manual work or introduce dependencies on external platforms, increasing complexity and management overhead.
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NEW QUESTION # 138
You are tasked with automating the retraining of a Snowpark ML model based on the performance metrics of the deployed model. You have a table 'MODEL PERFORMANCE that stores daily metrics like accuracy, precision, and recall. You want to automatically trigger retraining when the accuracy drops below a certain threshold (e.g., 0.8). Which of the following approaches using Snowflake features and Snowpark ML is the MOST robust and cost-effective way to implement this automated retraining pipeline?
- A. Implement an external service (e.g., AWS Lambda or Azure Function) that periodically queries the "MODEL_PERFORMANCE table using the Snowflake Connector and triggers a Snowpark ML model training script via the Snowflake API.
- B. Use a Snowflake stream on the 'MODEL_PERFORMANCE table to detect changes in accuracy, and trigger a Snowpark ML model training function using a PIPE whenever the accuracy drops below the threshold.
- C. Implement a Snowpark ML model training script that automatically retrains the model every day, regardless of the performance metrics. This script will overwrite the previous model.
- D. Create a Snowflake task that runs every hour, queries the 'MODEL_PERFORMANCE table, and triggers a Snowpark ML model training script if the accuracy threshold is breached. The training script will overwrite the existing model.
- E. Create a Dynamic Table that depends on the 'MODEL PERFORMANCE table and materializes when the accuracy is below the threshold. This Dynamic Table refresh triggers a Snowpark ML model training stored procedure. This stored procedure saves the new model with a timestamp and updates a metadata table with the model's details.
Answer: E
Explanation:
Option D is the most robust and cost-effective solution. Using a Dynamic Table ensures that retraining is triggered only when necessary (when accuracy drops below the threshold). The Dynamic Table's materialization event then kicks off a Snowpark ML model training stored procedure that automatically retrains the model. This stored procedure saves the new model with a timestamp and updates a metadata table, allowing for version control. This eliminates unnecessary retraining runs (cost savings) and provides full lineage of models. Option A can be wasteful as it retrains even if it's not required. Option B using Stream & Pipes doesn't trigger model re-training after data accuracy breach. Option C doesn't account for model performance leading to unnecessary retrains. Option E introduces external dependencies and complexity that are best avoided within the Snowflake ecosystem.
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NEW QUESTION # 139
You've built a regression model in Snowflake using Snowpark Python to predict customer churn. After evaluating the model on a holdout dataset, you generate a residuals plot. The plot shows a distinct 'U' shape. Which of the following interpretations and subsequent actions are most appropriate?
- A. The 'U' shape suggests that the learning rate is too high. Reduce the learning rate of the model.
- B. The 'U' shape suggests the model is missing important non-linear relationships. Consider adding polynomial features or using a non-linear model like a Random Forest or Gradient Boosting Machine.
- C. The 'U' shape indicates homoscedasticity. No changes to the model are necessary.
- D. The 'U' shape implies multicollinearity is present. Use techniques like Variance Inflation Factor (VIF) to identify and remove highly correlated features.
- E. The 'U' shape indicates that the residuals are normally distributed. This is a positive sign and no changes are required.
Answer: B
Explanation:
A 'U' shaped residuals plot indicates heteroscedasticity and a non-linear relationship is not being captured by the model. Options B is correct because adding polynomial features or using a non-linear model can help capture this relationship. The other options are incorrect because they misinterpret the meaning of the 'U' shape in the residuals plot or propose inappropriate remedies.
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NEW QUESTION # 140
A data scientist is performing exploratory data analysis on a table named 'CUSTOMER TRANSACTIONS. They need to calculate the standard deviation of transaction amounts C TRANSACTION AMOUNT) for different customer segments CCUSTOMER SEGMENT). The 'CUSTOMER SEGMENT column can contain NULL values. Which of the following SQL statements will correctly compute the standard deviation, excluding NULL transaction amounts, and handling NULL customer segments by treating them as a separate segment called 'Unknown'? Consider using Snowflake-specific functions where appropriate.
- A. Option A
- B. Option E
- C. Option D
- D. Option B
- E. Option C
Answer: D,E
Explanation:
Options B and C correctly calculates the standard deviation. Option B utilizes 'NVL' , which is the equivalent of 'COALESCE or ' IFNULL', to handle NULL Customer Segment values, and 'STDDEV_SAMP' for sample standard deviation, which is generally the correct function to use when dealing with a sample of the entire population. Option C also uses 'COALESCE and utilizes the 'STDDEV POP function, which returns the population standard deviation, assuming the data represents the whole population. Option A uses IFNULL, which works, and STDDEV, which is an alias for either STDDEV SAMP or STDDEV POP. The exact behavior will depend on session variable setting. Option D also uses 'CASE WHEN' construct which works to identify Unknown segments. STDDEV is again aliased. Option E calculates the variance and not Standard deviation.
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NEW QUESTION # 141
Which of the following statements about Z-tests and T-tests are generally true? Select all that apply.
- A. Both Z-tests and T-tests assume that the data is non-normally distributed.
- B. A Z-test requires knowing the population standard deviation, while a T-test estimates it from the sample data.
- C. A T-test is generally used when the sample size is large (n > 30) and the population standard deviation is known.
- D. As the sample size increases, the T-distribution approaches the standard normal (Z) distribution.
- E. A T-test has fewer degrees of freedom compared to the Z-test, making it more robust to outliers.
Answer: B,D
Explanation:
The correct answers are A and C. A Z-test requires knowing the population standard deviation, while a T-test estimates it from the sample data. As the sample size increases, the T-distribution approaches the standard normal (Z) distribution, which is a core concept in statistical inference. B is incorrect because a T-test is generally used for small sample sizes (n < 30) or when the population standard deviation is unknown. D is incorrect because both tests assume the underlying population distribution is approximately normal, especially for smaller sample sizes (though the Central Limit Theorem allows us to relax this assumption somewhat for large samples). E is incorrect because fewer degrees of freedom make the t-test less robust to outliers. Also the robustness is provided by the population distribution being approximately normal.
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NEW QUESTION # 142
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